Matematika Tolong kak bantu no 1a, sama 2B ka

Tolong kak bantu no 1a, sama 2B ka

Jawab:

1.a. 9

2.b 11

Penjelasan dengan langkah-langkah:

1. a. [tex]\lim_{x \to -2} \frac{-4x^{2} +6x-8 }{3x^{2}+7x-2 }[/tex]

[tex]\lim_{x \to -2} \frac{-4x^{2} +6x-8 }{3x^{2}+7x-2 } \\subtitusi x=-2 \\\frac{-4(-2)^{2} +6(-2)-8 }{3(-2)^{2}+7(-2)-2 }\\\frac{-16 -12-8 }{12-14-2 }\\\frac{-36 }{-4 }\\9[/tex]

2. b. [tex]\lim_{x \to 2} \frac{x^{2} +7x-18 }{x-2}[/tex]

[tex]\lim_{x \to 2} \frac{x^{2} +7x-18 }{x-2} \\ \lim_{x \to 2} \frac{(x-2)(x+9)}{(x-2)}\\\lim_{x \to 2} (x+9)\\(2+9)\\ 11[/tex]

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